Math Problem, Please help!!!!!!!!!?
The perimeter of a regulation singles tennis court is 220 feet and the length is 2 feet less than three times the width. What are the dimensions of the court?
The perimeter of a regulation singles tennis court is 220 feet and the length is 2 feet less than three times the width. What are the dimensions of the court?
perimeter = 2L+2W=220
we also know that the length is related to the width by:
L=3W-2
use this equation for L in the perimeter equation:
2(3W-2)+2W=220
6W-4+2W=220
8W=224
W=28
L=3W-2=3×28-2=84-2=82
check:
perimeter=2×82+2×28=164+56=220
so L=82 and W=28
2L + 2W = 220 (eqn 1)
L + 2 = 3W
so 2L +4 = 6W
so 2L = 6W -4 (eqn 2)
sub eqn 2 into eqn 1
6W – 4 +2W = 220
8W -4 = 220
8W = 224
W = 28 feet
so L = 82 feet
let the width be x
length = 3x -2
since perimeter= 220,
2(3x-2) + 2x = 220
6x – 4 + 2x = 220
8x = 224
x = 28
therefore, the width is 28 feet.
when x=28, length = 3 (28) -2
therefore, length = 82 feet
Hence, dimensions = 82 x 28 feet.
Hope this step by step allows you to understand =)
28 feet by 82 feet
2x + 2y = 220
So x + y = 110
ALso: y = 3x – 2
So: x + 3x – 2 = 110
4x – 2 = 110
4x = 112
x = 28
y = 3 x 28 – 2 = 82
check 28 + 82 = 110