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Math Problem, Please help!!!!!!!!!?

The perimeter of a regulation singles tennis court is 220 feet and the length is 2 feet less than three times the width. What are the dimensions of the court?

  1. kuiperbelt2003
    24. Mai 2010, 02:25 | #1

    perimeter = 2L+2W=220

    we also know that the length is related to the width by:

    L=3W-2

    use this equation for L in the perimeter equation:

    2(3W-2)+2W=220

    6W-4+2W=220

    8W=224
    W=28

    L=3W-2=3×28-2=84-2=82

    check:

    perimeter=2×82+2×28=164+56=220

    so L=82 and W=28

  2. Master Tonne
    24. Mai 2010, 02:25 | #2

    2L + 2W = 220 (eqn 1)

    L + 2 = 3W
    so 2L +4 = 6W
    so 2L = 6W -4 (eqn 2)

    sub eqn 2 into eqn 1

    6W – 4 +2W = 220
    8W -4 = 220
    8W = 224
    W = 28 feet
    so L = 82 feet

  3. Lll
    24. Mai 2010, 02:25 | #3

    let the width be x
    length = 3x -2
    since perimeter= 220,
    2(3x-2) + 2x = 220
    6x – 4 + 2x = 220
    8x = 224
    x = 28
    therefore, the width is 28 feet.
    when x=28, length = 3 (28) -2
    therefore, length = 82 feet

    Hence, dimensions = 82 x 28 feet.

    Hope this step by step allows you to understand =)

  4. Teach
    24. Mai 2010, 02:25 | #4

    28 feet by 82 feet

    2x + 2y = 220

    So x + y = 110

    ALso: y = 3x – 2

    So: x + 3x – 2 = 110

    4x – 2 = 110

    4x = 112

    x = 28

    y = 3 x 28 – 2 = 82

    check 28 + 82 = 110

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